Tugas Soal pemetaan array dimensi 3 ke storage

BERIKUT ADALAH CONTOH SOAL PEMETAAN ARRAY DIMENSI TIGA KE STORAGE

(soal 1.)

suatu array A di deklarasikan sbb:
Float A[5][5][5] dengan alamat awal A[0][0][0] = 0021(H), berapakah alamat array A[2][3][2] dan A[5][4][3] ?
- jawaban :

# Array A[2][3][2]
- dik : Float A[5][5][5]
        A[0][0][0] = 0021(H)
        L = 4
- A[m][n][p] = M [0][0][0] + {((m-1) x (jum.elmn 2 x jum.elmn 3)) + ((n-1)x jum.elm 3) + ((p-1)) } x L
- A[2][3][2]  = 0021 (H) + { 25 + 10 + 1 } x 4
                    = 0021 (H) + 144 (D)
                    = 0021 (H) + 9 (H)
                    = 0030 (H)

# Array A[5][4][3]
- dik : Float A[5][5][5]
        A[0][0][0] = 0021(H)
        L = 4
- A[m][n][p] = M [0][0][0] + {((m-1) x (jum.elmn 2 x jum.elmn 3)) + ((n-1)x jum.elm 3) + ((p-1)) } x L
- A[5][4][3]  = 0021 (H) + { 100 + 15 + 2 } x 4
                     = 0021 (H) + 468 (D)
                     = 0021 (H) + 1D4 (H)
                     = 1F5 (H)



(Soal 2).

suatu array di deklarasikan sbb :
Char B[3][4][3] dengan alamat awal A[0][0][0] = 0021(H) , berapakah alamat array A[2][3][2] dan A[3][4][3]

- jawaban :
# Char B[2][3][2]
- dik : Float A[3][4][3]
        A[0][0][0] = 0021(H)
        L = 1
- A[m][n][p] = M [0][0][0] + {((m-1) x (jum.elmn 2 x jum.elmn 3)) + ((n-1)x jum.elm 3) + ((p-1)) } x L
- A[2][3][2]   = 0021 (H) + { 12 + 6 + 1 } x 1
                      = 0021 (H) + 19 (D)
                      = 0021 (H) + 13 (H)
                      = 0034 (H)

# Char B[3][4][3]
- dik : Float A[3][4][3]
        A[0][0][0] = 0021(H)
        L = 1
- A[m][n][p] = M [0][0][0] + {((m-1) x (jum.elmn 2 x jum.elmn 3)) + ((n-1)x jum.elm 3) + ((p-1)) } x L
- A[3][4][3]   = 0021 (H) + { 24 + 9 + 2 } x 1
                      = 0021 (H) + 35 (D)
                      = 0021 (H) + 23 (H)
                      = 0044 (H)

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